gate 2017 EE(Set-B) q40-solution

gate 2017 EE(Set-B) q40-solution

gate 2017 EE(Set-B) q40-solution,Answer Key & Full Solutions to GATE 2017 Questions Papers for All brahes .Full Solutions to GATE 2017 Questions Paperswe have syllabus of

gate 2017 EE(Set-B) q40-solution

gate 2017 EE(Set-B) q40-solution search engine Keywords Thesis 123

  • gate 2017 EE(Set-B) q40-solution
  • gate paper
  • gate question paper
  • gate 2017 question paper with solution
  • gate previous papers
  • gate solved papers/li>
  • gate 2017 question paper
  • gate question bank
  • gate question paper with solution
  • gate electrical engineering
  • gate model papers
  • gate sample papers
  • gate 2017 key
  • gate previous year papers
  • gate papers for electronics and communication
  • gate previous year question papers with solutions for ece
  • gate paper for mechanical engineering
  • gate online test
  • gate previous year question papers with solutions
  • gate solved question papers
  • gate mechanical solved papers
  • gate previous year question papers with solutions for cse
  • gate test papers
  • gate civil engineering solved papers pdf
  • gate online coaching
  • gate solved papers for mechanical engineering
  • made easy gate previous papers
  • gate question bank for mechanical engineering
  • gate previous papers with solutions for mechanical
  • gate ece solved papers
  • gate question bank for mechanical
  • gate civil previous papers with solutions
  • made easy solved paper of gate
  • gate engineering mathematics previous years question papers with solutions
  • gate previous papers with solutions for cse
  • gate ee previous papers
  • gate previous year papers for mechanical
  • gate previous year question papers with solutions for engineers
  • gate 10 years solved papers
  • made easy gate papers

$$V_{or}=\frac{V_m}{2}$$
$$V_m=\sqrt{2V_s}$$
$$I_{or}=\frac{V_{or}}{R}=\frac{V_m}{2R}$$
$$\frac{V_m}{2}=\frac{\sqrt{2}}{2}V_s=\frac{V_s}{\sqrt{2}}$$
IPF $$=\frac{P_{load}}{inputVA}=\frac{V_{or}I_{or}}{V_SI_{or}}=\frac{V_{or}}{V_s}=\frac{V_s}{\sqrt{2}V_s}=\frac{1}{\sqrt{2}}=0.707$$