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Gate 2016 Set 2 - EE Question 1 - Solution

Gate 2016 Set 2 - EE

Question 1 - Solution 

Pairing the 1's in the map given, results in three sets.

Two pair's of 1's result in B\bar{C} and \bar{B}\bar{C}

One set of four 1's results in A

Therefore, F = A + B\bar{C} + \bar{B}\bar{C}

F = A + \bar{C}(B + \bar{B})

F = A + \bar{C}      Since, (B + \bar{B} = 1)

Thus, the right option is (B)

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