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GATE 2016 EE -SET 2 Question 26

\overline{(a+\bar{b}+c+\bar{d})+(b+\bar{c})} =\overline{a+\bar{b}+c+\bar{d}}\cdot \overline{b+\bar{c}}

\left [ \because \overline{a+b}=\bar{a}\cdot \bar{b} \right ] de Morgan's theorem.

\Rightarrow (\bar{a}\cdot b\cdot \bar{c}\cdot d)(\bar{b}\cdot c)=0

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