# GATE 2016 – E E – SET 2 Question 12

Average Power, P = $$V_{rms}I_{rms}\cos\phi\Rightarrow \frac{V_{m}}{\sqrt{2}}\ast \frac{I_{m}}{\sqrt{2}}\cos\phi$$

P = $$\frac{100}{\sqrt{2}}\ast \frac{10}{\sqrt{2}}\cos (60)$$ = 250 Watts