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GATE 2016 - E E - SET 2 Question 12

Average Power, P = V_{rms}I_{rms}\cos\phi\Rightarrow \frac{V_{m}}{\sqrt{2}}\ast \frac{I_{m}}{\sqrt{2}}\cos\phi

P = \frac{100}{\sqrt{2}}\ast \frac{10}{\sqrt{2}}\cos (60) = 250 Watts

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