Home » Uncategorized » GATE 2015 EE - SET 2 - Question 4

GATE 2015 EE - SET 2 - Question 4

Solution :

f(t) = 2\sqrt{\frac{t}{T}}

{f}'(t)= \frac{2}{\sqrt{\pi }} . \frac{1}{2\sqrt{t}}

\Rightarrow \frac{1}{\sqrt{\pi }t}

\Rightarrow \sqrt{\frac{1}{\pi t}}

\Rightarrow g(t)

L\left [ {f}'(t) \right ] = SL \left [ f(t) \right ] - f (0)

L\left [ {f}'(t) \right ] =  S\left [ S^{\frac{-3}{2}} \right ] - 2\sqrt{\frac{0}{\pi }}

S^{1}(S^{\frac{-3}{2}}) = S ^{\frac{-1}{2}}

Translate »