GATE 2015 EE – SET 2 – Question 31

Solution :

D = 0.6 , $$V_{0}$$ = 36 V , f = 100kHz = 100 * $$10^{3}$$Hz

$$I_{0}$$ = $$\frac{DV_{in}}{R}$$

Inductor ripple current , $$\Delta I_{L}$$=$$\frac{D(1-DV_{in})}{2fL}$$

$$\Delta I_{L}$$=$$I_{0} $$

$$\frac{D(1-D)V_{in}}{2fL}$$ = $$\frac{DV_{in}}{R}$$

R = $$\frac{2fL}{1-D} $$$$ \Rightarrow$$$$ \frac{2*100*10^{3}*5*10^{-3}}{1-0.6}$$

R = $$\frac{1000}{0.4}$$ = 2500 Ω