GATE 2015 EE – SET 2 – Question 22

Solution :

Rotor current , I = $$\frac{V_{g}}{1 +j0.22}$$ = $$\frac{210}{1 + j0.22} $$= 205.09

P = 3$$I^{2}$$R = 3 *$$ (205.09)^{2}$$ * 1 = 126185.72

 

Torque = $$\frac{P}{W} $$= $$\frac{126185.72}{2\pi f} $$
$$\tau$$=$$\frac{126185.72}{2*3.14*50}$$ = 401.66 N-m