GATE 2015 EE - SET 2 - Question 22

Solution :

Rotor current , I = \frac{V_{g}}{1 +j0.22} = \frac{210}{1 + j0.22} = 205.09

P = 3I^{2}R = 3 * (205.09)^{2} * 1 = 126185.72

 

Torque = \frac{P}{W} = \frac{126185.72}{2\pi f}
\tau=\frac{126185.72}{2*3.14*50} = 401.66 N-m