# GATE 2015 EE - SET 2 - Question 12

For$V_{c}$ = 2
$R_{c}$= ${\frac{10-V_{c}}{I_{c}}}$ = $\frac{10-2}{I_{c}}$ =$\frac{8}{I_{c}}$

For $V_{c}$ = 4 ,

$\acute{R_{c}}$ = ${\frac {10-V_{c}}{I_{c}}}$ = $\frac{10-4}{I_{c}}$ = $\frac{6}{I_{c}}$

$\frac{\acute{R_{c}}}{R_{c}}$= $\frac{\frac{6}{I_{c}}}{\frac{8}{I_{c}}}$=$\frac{6}{8}$= 0.75