Home » Uncategorized » GATE 2015 EE - SET 1 - Question 43

GATE 2015 EE - SET 1 - Question 43

Solution :

\delta = \frac{P_{a}t^{2}}{2M} , where M = \frac{H}{f*180}

where H is the ratio of the stored KE to machine rating

H = 2 , f = 50 ,t = 0.02 ,P=1 pu

\delta = \frac{P_{a}t^{2}}{2M} =  \frac{Pt^{2}}{2*\frac{H}{f*180}}

\delta = \frac{1*(0.02)^{2}}{2*\frac{2}{50*180}} = 0.9

\delta = 5 +0.9 = 5.9^{0}

 

Translate »