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GATE 2015 EE - SET 1 - Question - 40

Solution :

8 - bit SAR , V_{ref} = +5V

Resolution ⇒ k =  \frac{V_{ref}}{2^{n}} = \frac{5}{2^{8}} = 0.0195

Applied input voltage = 3.5V

  1. After the first clock pulse : MSB ⇒ 0 ------- (1) , output of SAR ⇒ 10000000
  2. After the second clock :7th bit from 0 ------(1) , output = 11000000 = 10000000
  3. At the third clock pulse : SAR will toggle its 6 ^{th} bit 0 -----> 1
    10000000 = 10100000

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