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GATE 2015 EE - SET 1 Question 34

Solution :

N_{s} = Synchronous speed

\phi = 3 , f = 50 Hz , P = 4 ,

5^{th} harmonic = \frac{N_{s}}{5}

N_{s} = \frac{120f}{p} = \frac{120*50}{4}= 1500 rpm

5^_{th} harmonic  =  \frac{N_{s}}{5} = \frac{1500}{5} = 300 rpm

slip \Rightarrow  \frac{N_{s}+\frac{N_{s}}{5}}{N_{s}}

 \frac{1500+300}{1500} =1.2

\frac{1+\frac{1}{5}}{1}=\frac{6}{5}=1.2

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