GATE 2015 EE – SET 1 – Question 33

Solution :

$$V_{0} $$ = m * $$\frac{2\sqrt{2}V_{s}}{\pi }$$ ,

Whe$$V_{0} $$ = m * $$\frac{2\sqrt{2}V_{s}}{\pi }$$ re f = 50 Hz , $$f_{s}$$ = 50 * $$10^{3}$$Hz  , m = 0.7 , $$v_{in} $$= 100 V , L = 9.55 * $$10 ^{-3} $$, C = 63.66 * $$10 ^{-6}$$

$$V_{0} $$ = m * $$\frac{2\sqrt{2}V_{s}}{\pi }$$

$$V_{0} $$= $$\frac{0.7*2\sqrt{2}*100}{3.14}$$ = 63.05 V