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# GATE 2015 EE - SET 1 - Question 33

Solution :

$V_{0}$ = m * $\frac{2\sqrt{2}V_{s}}{\pi }$ ,

Whe$V_{0}$ = m * $\frac{2\sqrt{2}V_{s}}{\pi }$ re f = 50 Hz , $f_{s}$ = 50 * $10^{3}$Hz  , m = 0.7 , $v_{in}$= 100 V , L = 9.55 * $10 ^{-3}$, C = 63.66 * $10 ^{-6}$

$V_{0}$ = m * $\frac{2\sqrt{2}V_{s}}{\pi }$

$V_{0}$= $\frac{0.7*2\sqrt{2}*100}{3.14}$ = 63.05 V

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