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GATE 2015 EE - SET 1 - Question 33

Solution :

V_{0} = m * \frac{2\sqrt{2}V_{s}}{\pi } ,

WheV_{0} = m * \frac{2\sqrt{2}V_{s}}{\pi } re f = 50 Hz , f_{s} = 50 * 10^{3}Hz  , m = 0.7 , v_{in} = 100 V , L = 9.55 * 10 ^{-3} , C = 63.66 * 10 ^{-6}

V_{0} = m * \frac{2\sqrt{2}V_{s}}{\pi }

V_{0} = \frac{0.7*2\sqrt{2}*100}{3.14} = 63.05 V

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