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GATE 2015 EE - SET 1 Question - 31

Solution :

Average output voltage V_{o}

V_{o} = \frac{V_{1}t_{1}+V_{2}t_{2}}{T}

Where V_{1} = 10 V ,V_{2} = 5 V ,t_{1} =0.2 * 10 ^{-3} , t_{2} = 0.3 * 10^{-3} ,T = 0.5 *10^{-3}

V_{o} = \frac{(10)(0.2m)+(5)(0.3m)}{(0.5)(m))}

V_{0} = 7V

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