# GATE 2015 EE – SET 1 Question – 31

Solution :

Average output voltage $$V_{o}$$

$$V_{o}$$ = $$\frac{V_{1}t_{1}+V_{2}t_{2}}{T}$$

Where $$V_{1}$$= 10 V ,$$V_{2}$$ = 5 V $$,t_{1}$$ =0.2 * $$10 ^{-3}$$ ,$$t_{2}$$ = 0.3 * $$10^{-3}$$ ,T = 0.5 *$$10^{-3}$$

$$V_{o}$$ = $$\frac{(10)(0.2m)+(5)(0.3m)}{(0.5)(m))}$$

$$V_{0}$$ = 7V